Genetics: Bacterial


 

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Chapter 6. Genetic Transfer and Mapping in Bacteria and Bacteriophages.

•      Bacteria reproduce asexually so researchers rely on genetic transfer instead of crosses.

–   A segment of bacterial chromosome is passed from one bacterium to another.

–   Used to map gene locations along the single circular chromosome.

–   We will also discuss genetic mapping in bacterial viruses or bacteriophages.

–   There are three naturally occurring ways that genetic material can go from one bacterium to another: conjugation, transduction and transformation.

•   Conjugation:

•   Transduction: A virus that infects bacteria (bacteriophage) transfers genetic material from one bacterium to another.

•   Transformation: Genetic material from one cell is released into the environment (death) and another bacterium takes it up.

•   Joshua Lederberg and Edward Tatum were the first to demonstrate the natural ability of bacteria to transfer genetic material.

•   They were studying a strain of E. coli called B-M-P+T+ that had certain growth requirements.

–  Required the vitamin biotin (B), the amino acid methionine (M); and did not require phenylalanine (P) and threonine (T).

–  Another strain B+M+P-T- had the opposite requirements.

–  These differences in requirements were the result of differences in DNA.

•   The B-M-P+T+ has defects in a gene encoding for an enzyme involved in the biotin and methionine biosynthetic pathways.

•   The B+M+P-T- has defects in a gene encoding for an enzyme involved in the phenylalanine and threonine biosynthetic pathways.

•   If either of these strains are grown and plated at a concentration of 109 cells on plates that do not have amino acids or biotin they will not grow.

•   However, if you mix the two cells together and plate 109 cells approximately 100 cells will grow.

•   Lederberg and Tatum surmised that genetic material was being transferred between the two cell types.

•   This allowed the two bacteria to form new bacteria that were B+M+P+T+.

•   This was further established with the U-tube that would only allow small molecules to pass between the two halves of the tube.

•   Only about 5% of bacteria can act as donors.

•   Donor strains contain a small circular segment of DNA (plasmid) known as F (fertility) factor these strains are denoted F+.

•  

•   The sex pili act as an attachment site and allows for physical contact between F+ and F- strains.

•   One strand of the F factor plasmid is transferred to the recipient cell.

–  This transfer begins at a site called the origin of transfer.

–   Hfr strains of E. coli contain F+ factor integrated into the chromosome and during conjugation the bacterial chromosome is transferred from the donor to the recipient in a linear fashion.

•   These strains will also transfer chromosomal genes to the recipient cell.

•   Hfr stands for high frequency of recombination.

•   F factor has become integrated into the chromosome.

•  

•   The origin of transfer is the first place that is cut and readied for transfer.

•   From this starting point all the bacterial chromosome enters the F- recipient cell in a linear manner.

•   Once inside the F- bacterium this DNA can swap or recombine with the recipients own chromosome.

•   This recombination may result in a new combination of alleles.

•   Ex: A recipient strain that is lac- (unable to metabolize lactose) and pro- (unable to metabolize proline) The donor cell in this case is lac+ and pro+.

•   Depending on the length of mating the recipient cell could become lac+ or both lac+ and pro+.

•   Since the chromosomal DNA is passed to the F- cell in a linear fashion a longer the mating time will result in more chromosomal DNA being passed to the recipient cell.

•   In this example lac is always transferred before pro due to the orientation of the origin of transfer.

•   Different Hfr strains have different locations for their origins of transfer and different orientations.

–   Wolling and Jacob used Hfr matings to map genes along the E. coli chromosome.

–  

•   Used a blender at speeds that separate conjugating bacteria but do not destroy the cells.

–   The rationale behind their study was that the time it takes for a gene to be transferred to the recipient cell is directly related to their order on the chromosome.

•   They realized since the chromosome is transferred linearly interrupting conjugation at different times would lead to various lengths of the Hfr chromosome entering the recipient cell.

•   By determining which genes were transferred during quick matings and which were transferred during slow matings they could order the genes along the E. coli chromosome.

•   The donor strain’s genetic composition.

–  T+: synthesizes threonine.

–  L+: Synthesizes leucine.

–  Azs: Sensitive to the toxic chemical azide.

–  T1s: Sensitive to bacteriophage T1 infection.

–  Lac+: Metabolizes lactose and use it for growth.

–  Gal+: Metabolizes galactose and use it for growth.

–  Strs:

•   The recipient strain has the opposite genotypes for these genes: T-, L-, Azr, T1r, lac-, gal-, and strr where r = resistant.

•   They knew that the T gene was transferred first and the L gene second both after 5-10 minutes of mating.

•   The goal of the experiment was to determine the times at which Azs, T1s, lac+ and gal+ where transferred.

–  Strs was not examined because streptomycin was used to kill the donor strain.

–   Hypothesis: The chromosome of the donor strain is transferred in a linear fashion to the recipient strain. The order of the genes along the chromosome can be deduced by determining the time various genes take to enter the recipient strain.

–   How did they test for gene transfer?

•   First took mated cells and plated them on plates lacking threonine and leucine but had streptomycin.

–  This made sure that neither the original donor or recipient strains could grow. How?

•   The recipient cells that had received the T+ and L+ genes would be able to survive.

•   In order to determine the order of transfer of the Azs, T1s, lac+ and gal+ genes the experimenters picked colonies from the above plate and streaked them on plates that had azide or bacteriophage T1, or on minimal plates that contained either lactose or galactose as the sole energy source.

•   These plates are then incubated overnight and analyzed for growth.

–  Recipient cells that have received the Azs gene cannot grow on azide.

– 

–  If the recipient has received the lac+ gene it will grow on plates that only have lactose as an energy source.

–  If the recipient has received the gal+ gene it will grow on plates that only have galactose as an energy source.

–   Interpretation of data:

•   After the first plating all survivors would be F- cells that have received T+ and L+ alleles and F- cells are already resistant to streptomycin.

–  Transfer of T+ and L+ occurred after 10 minutes.

•   Each of the surviving T+,L+ colonies were then tested for the transfer of the remaining genes (Azs, T1s, lac+ and gal+).

–  Where the colonies sensitive to killing by azide, infection by T1, able to utilize lactose or able to utilize galactose?

–  After how much mating time did each of these phenotypes appear?

•   A pattern emerged.

–  The gene conferring sensitivity was transferred before the gene conferring sensitivity to T1 phage infection.

–  The transfer of these two genes was followed by lac+ and then finally gal+.

•   From this data a map can be generated.

 

 

 

 

 

 

•   Studied many Hfr strains and their data was consistent with a circular E. coli chromosome.

–   Conjugation studies have resulted in a detailed genetic map of the E. coli chromosome.

•   Mapped 1,000 genes of the E. coli chromosome.

•   The arbitrarily assigned starting point is at 0 minutes and the chromosome is 100 minutes long.

•   Which is the time it takes to transfer the complete Hfr chromosome during mating.

•   Maps generated from bacterial conjugation studies are are illustrated using the unit minutes.

–   Bacteriophages can also transfer genetic material from one bacterium to another via transduction.

•   Bacteriophages contain genetic material surrounded by a complex protein coat.

•   Bacteriophages attach to the surface of a bacteria and inject there genetic material.

• 

•   Lysogenic cycle: Phage DNA inside the bacterium integrates into the chromosome (creates a prophage) of the cell and is reproduced along with bacterial reproduction.

•   Lytic cycle: The bacteriophage directs synthesis of multiple copies of the phage genetic material and coat proteins.

–  These components are assembled as phages which then lyse the host cell and infect other cells.

•   Cells can begin in the lysogenic cycle and enter the lytic cycle at a later time.

–  The prophage exits the bacterial chromosome initiating the lytic cycle.

•   When certain phages enter the lytic cycle the bacterial chromosome becomes fragmented.

•   These fragments are sometimes packaged inside bacteriophage coat proteins and delivered into a new bacterium.

•   These fragments of DNA are then free to integrate into the new cell resulting in a new combination of alleles.

•   This type of transduction is called generalized transduction.

–   If two genes are close together on the bacterial chromosome they may be packaged in a single bacteriophage and transferred as a single unit, cotransduction.

•   The likelihood of cotransduction depends on the distance between the two genes.

•   A bacteriophage cannot physically carry DNA fragments larger than 1-2.5% of the bacterial genome.

•   Cotransduction frequency = (1-d/L)3

•   d= distance between the genes in minutes and L= size of chromosomal pieces.

–   Bacteria can transfer genetic material by transformation.

•  

•   The DNA fragment may then incorporate into the recipient cell making a recombinant bacterium.

•   Competent cells are special bacterial cells that can undergo transformation.

–  These cells are influenced by ionic concentration, temperature, and nutrients in their environment.

–  A fragment of DNA binds to the surface of the bacterial cell.

•   The DNA is then cleaved by an endonuclease to a manageable size.

•   The DNA interacts with proteins from the cell surface and either one or both strands is brought into the cell.

•   This DNA then may be incorporated into the recipients chromosome.

•   If a single strand has been taken up and is recombining into the chromosome sometimes a heteroduplex may form.

–  Heteroduplex: region of mismatch.

•   These are fixed by DNA repair enzymes and can be used to repair mutations in bacteria.

 

•      Intragenic Mapping of Bacteriophages.

–   Viruses are not living, however they do have traits.

•   They are a product of their genetic material.

–   We will focus on bacteriophage T4 which has several dozen genes that make up its genetic material.

•   These genes encode for proteins necessary for the viral “life” cycle.

–  Proteins involved in coat assembly, lysis etc..

–  Example: Tail fiber proteins that allow it to attach to bacterium.

»  Bacteriophage specific proteins.

–   Seymour Benzer (early 1950’s) did much early work on bacteriophage DNA that led to a basic understanding of all genetic material.

•  

–  Intragenic mapping (fine structural mapping):  Is the mapping of the sequence differences between two alleles of the same gene.

–  Intergenic mapping figures the distance between two genes.

 

 

 

 

–   Lytic bacteriophages produce viral plaques.

•   Lytic phages cause lysis of the host cell so the newly formed phages can infect more cells.

–  This cycle causes areas on a plate where all the bacterial cells have been lysed.

–  These areas appear as plaques (an observable clear area) on a lawn of bacteria.

•   Mutational analysis of phages resulted in phages that would cause different plaque morphologies.

•   rII T4 phage resulted in a few plaques that were abnormally large.

•   This phage variant forms different plaques depending on the bacterial strain it infects.

–   Complementation can reveal if mutations are in the same gene.

•   How can two different mutations affect one trait?

•   One way is that the two mutations may be in the same gene.

–  What is the other way? Example?

•   Phage mutations can be examined by coinfecting cells with two phages that have mutants that affect the same trait.

–  What would happen if the mutants were in the different genes?

–  The same gene?

–  Complementation: The mutations were in different genes allowing one wild-type gene from each phage to complement the mutant gene of the other phage.

»  Able to form plaques.

–  Noncomplementation:  Coinfection does not allow for plaque formation since both phages had mutations in the same gene.

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»  Cistron = gene.

»  His studies on rII phage resulted in the identification of two genes involved rIIA and rIIB.

–   Intragenic maps were generated using data from recombination within the rII region.

•   At an extremely low rate two noncomplementing strains can produce a plaque.

–  Cannot be homoallelic mutants (the same mutation).

•   How?

–  Crossover between the two mutations within the gene.

–  Probably as infrequently as 1 in 100,000.

–  Needs to be a rapidly reproducing organism.

•   Benzer used this rarely occurring recombination event to measure the distance between the two mutations (intragenic distance).